We found the equation of the sine function to be:
$$ \sin(x)=xr(x)\prod_{n=1}^{\infty}{1-\frac{x2}{n2 \pi2}} $$
Knowing that $r(0)=1$ and $r$ is an even function. How do we show that that $r(x)=r(0)$ for all $x$?
More here; https://piecewise.org/questions/euler-sine-product-2
Solved 🙂
Was a pain in the butt, worked all day on this...oops.
